/*
 * Copyright (c) 2019, 2020, Oracle and/or its affiliates.
 *
 * All rights reserved.
 *
 * Redistribution and use in source and binary forms, with or without modification, are
 * permitted provided that the following conditions are met:
 *
 * 1. Redistributions of source code must retain the above copyright notice, this list of
 * conditions and the following disclaimer.
 *
 * 2. Redistributions in binary form must reproduce the above copyright notice, this list of
 * conditions and the following disclaimer in the documentation and/or other materials provided
 * with the distribution.
 *
 * 3. Neither the name of the copyright holder nor the names of its contributors may be used to
 * endorse or promote products derived from this software without specific prior written
 * permission.
 *
 * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND ANY EXPRESS
 * OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
 * MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE
 * COPYRIGHT HOLDER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL,
 * EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE
 * GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED
 * AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING
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 * OF THE POSSIBILITY OF SUCH DAMAGE.
 */

/* The corresponding bitcode file was produced with:
 * clang -Wall -Wextra -mavx2 -mavx -fvectorize -O1 -c -emit-llvm gep-vec.c
*/
// void doloop(float *a[512], float b[512], int c[512], int d[512]) {
//   for (int i = 0; i < 512 / 4; ++i) {
//     #pragma clang loop vectorize(enable)
//     for (int j = 0; j < 4; ++j) {
//       a[(i*4)+j] = &b[(i*4)+j] + c[(i*4)+j] * d[(i*4)+j];
//     }
//   }
// }
void doloop(float *a[512], float b[512], int c[512], int d[512]);

void init(int c[512], int d[512]) {
    for (int i = 0; i < 512; i++) {
        c[i] = i;
        d[i] = i + 512;
    }
}

int main() {
    float *a[512];
    float b[512];
    int c[512] = { 0 };
    int d[512] = { 0 };

    init(c, d);
    doloop(a, b, c, d);

    for (int i = 0; i < 512; ++i) {
        if (a[i] != &b[i] + c[i] * d[i]) {
            return 1;
        }
    }

    return 0;
}
